在JAVA中如何跳出當(dāng)前的多重嵌套循環(huán)?

　　在Java中，我們可以使用break語句來跳出當(dāng)前循環(huán)。如果我們需要跳出多重嵌套循環(huán)，可以使用帶標(biāo)簽的break語句。

　　下面是一個(gè)使用帶標(biāo)簽的break語句跳出多重嵌套循環(huán)的示例代碼：

outerloop:
for (int i = 0; i < 10; i++) {
  for (int j = 0; j < 10; j++) {
    if (i == 5 && j == 5) {
      break outerloop;
    }
    System.out.println("i = " + i + ", j = " + j);
  }
}

　　在這個(gè)示例代碼中，我們使用outerloop標(biāo)簽來標(biāo)識外部循環(huán)。當(dāng)i和j的值都等于5時(shí)，我們使用break語句和標(biāo)簽outerloop跳出外部循環(huán)。

　　當(dāng)運(yùn)行這個(gè)示例代碼時(shí)，它將輸出：

i = 0, j = 0
i = 0, j = 1
i = 0, j = 2
i = 0, j = 3
i = 0, j = 4
i = 0, j = 5
i = 0, j = 6
i = 0, j = 7
i = 0, j = 8
i = 0, j = 9
i = 1, j = 0
i = 1, j = 1
i = 1, j = 2
i = 1, j = 3
i = 1, j = 4
i = 1, j = 5
i = 1, j = 6
i = 1, j = 7
i = 1, j = 8
i = 1, j = 9
i = 2, j = 0
i = 2, j = 1
i = 2, j = 2
i = 2, j = 3
i = 2, j = 4
i = 2, j = 5
i = 2, j = 6
i = 2, j = 7
i = 2, j = 8
i = 2, j = 9
i = 3, j = 0
i = 3, j = 1
i = 3, j = 2
i = 3, j = 3
i = 3, j = 4
i = 3, j = 5
i = 3, j = 6
i = 3, j = 7
i = 3, j = 8
i = 3, j = 9
i = 4, j = 0
i = 4, j = 1
i = 4, j = 2
i = 4, j = 3
i = 4, j = 4
i = 4, j = 5
i = 4, j = 6
i = 4, j = 7
i = 4, j = 8
i = 4, j = 9

　　可以看到，當(dāng)i和j的值都等于5時(shí)，外部循環(huán)被中斷，并且程序直接跳出循環(huán)，沒有輸出剩余的i和j的值。

　　需要注意的是，帶標(biāo)簽的break語句只能用于循環(huán)語句中，不能用于其他類型的語句中。此外，continue語句也可以使用帶標(biāo)簽的形式，用于在多重嵌套循環(huán)中跳過當(dāng)前迭代并繼續(xù)下一次迭代。